fix compiling with Xcode 26

Author: bo2themax

Package.swift

@@ -261,9 +261,14 @@ var dependencies: [Package.Dependency] = [
     .package(url: "https://github.com/swiftlang/swift-syntax.git", from: "600.0.0"),
     .package(url: "https://github.com/Quick/Quick.git", from: "3.0.0"),
     .package(url: "https://github.com/Quick/Nimble.git", from: "9.0.0"),
-    .package(url: "https://github.com/art-divin/swift-package-manager.git", exact: "1.0.8"),
 ]
 
+#if compiler(>=6.2)
+dependencies.append(.package(url: "https://github.com/swiftlang/swift-package-manager.git", revision: "5c57a39"))
+#else
+dependencies.append(.package(url: "https://github.com/art-divin/swift-package-manager.git", exact: "1.0.8"))
+#endif
+
 #if !canImport(ObjectiveC)
 dependencies.append(.package(url: "https://github.com/apple/swift-crypto.git", from: "3.0.0"))
 #endif

SourceryFramework/Sources/Parsing/SwiftSyntax/AST/GenericType+SwiftSyntax.swift

@@ -4,9 +4,21 @@ import SwiftSyntax
 
 extension GenericType {
     convenience init(name: String, node: GenericArgumentClauseSyntax) {
+        #if compiler(>=6.2)
+        // TODO: ExprSyntax may need to be handled
+        let parameters = node.arguments.map { argument -> GenericTypeParameter? in
+            switch argument.argument {
+            case .type(let type):
+                return GenericTypeParameter(typeName: TypeName(type))
+            default: // case .expr
+                return nil
+            }
+        }.compactMap({ $0 })
+        #else
         let parameters = node.arguments.map { argument in
             GenericTypeParameter(typeName: TypeName(argument.argument))
         }
+        #endif
 
         self.init(name: name, typeParameters: parameters)
     }